I'd say your best chance is just launching an Android version with a controller (I assume Android version supports controllers). It's just that nobody on PC plays Bedrock. All the community content (mods, resource packs, custom tools) is for the original version, after all, and Bedrock is a walled garden.
TwilightKiddy
joined 2 years ago
If you confused period and fax intentionally, I commend the effort.
Considering vibe is probalby float, I doubt any exceptions can be thrown there, you can eliminate another useless scope.
Even if it's not float, I'd consider burning alive anyone who overrides an operator like this anyway.
Stuff like BSD, Minix, maybe some curios individuals on Solaris? For mobile, Symbian, Windows Mobile? Also, probably all that don't report their OS in the user agent.
I know a couple of Japanese people running Linux on their desktops. So, I say the counting method is borked somewhere.
Or get into NFTs? That community would gladly overexplain the term "fungibility" to you. Just give your wallet to someone you trust for safekeeping while you do your research.
I only remember useful things. And I consider these useful because I did some low level graphics programmed once and had to use them in practice. Once you understand why these things exist, it becomes that much easier.
If someone didn't learn enough trigonometry in school:
1+tan^2^c = cos^2^c/cos^2^c + sin^2^c/cos^2^c = (cos^2^c + sin^2^c)/cos^2^c = 1/cos^2^c;
sqrt(1/cos^2^c) = |sec c|
And here is for the people who still don't get the joke
The reading of the answer is very similar to the word "sexy", which makes the whole sentence a reference to the song "Sexy and I Know It" by LMFAO.
Well, on the side of easy ones there is "if the last digit is divisible by 2, whole number is divisible by 2". Also works for 5. And if you take last 2 digits, it works for 4. And the legendary "if it ends with 0, it's divisible by 10".
The divisability rule for 7 is that the difference of doubled last digit of a number and the remaining part of that number is divisible by 7.
E.g. 299'999 → 29'999 - 18 = 29'981 → 2'998 - 2 = 2'996 → 299 - 12 = 287 → 28 - 14 = 14 → 14 mod 7 = 0.
It's a very nasty divisibility rule. The one for 13 works in the same way, but instead of multiplying by 2, you multiply by 4. There are actually a couple of well-known rules for that, but these are the easiest to remember IMO.
If something does not work, mostly it either has a kernel level anticheat or it's Adobe. I just learned to live without these, I think it's for the best. You can even do VR on Linux nowadays!