this post was submitted on 15 May 2025
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Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.
But its height cannot be half of base because of the same Pythagorean theorem
(1,5)²+(1,5/2)²=2,8125
sqrt(2,8125) ≈ 1,677, which is half of a diagonal
So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture
TL;DR: Won't work because Pythagorean theorem
It's funny how we say "because of such and such theorem" as if if some greek dude didn't come up with his little story, the height could totally be half of base.
Babylonians had it figured it somewhat out for astronomy purposes about a thousand years before the weird bean hater.
Decolonialize Maths!
We do need short names, but they don't all have to be wyt guys. Pre-globalization, I'm sure many true maths statements were independently discovered by many people.
Pyramid?
Yes, it is possible with a 3-sided pyramid, i.e. tetrahedron. If we dont look at all 4 points as being on the same plane but 2 opposite corners being offset above or below the other two, this could totally be a tatrahedron.
So those two darker green symbols would represent someone shorter or taller. Totally plausible.
Wdym?
They could each be on the vertices of a tetrahedron for all we know...
We do know that, with those measurements, they aren't confined to a single (Euclidean) plane.
Exactly! I regret that I have but one upvote to give.
I was thinking of plane surfaces, but if their altitudes are different, I guess it'd be possible.