this post was submitted on 14 Feb 2024
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submitted 1 year ago* (last edited 11 months ago) by [email protected] to c/[email protected]
 
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[–] [email protected] 1 points 1 year ago

Oh, that makes warnings errors and does not mean "ignore errors". I'm not too familiar with compiler flags. You could do some mental gymnastics to argue that the unused variable causes the compiler to exit and thus the code is not functioning and thus the unused variable is not a warning but an error :^)