hinterlufer

The thing about the ones I've tried is that they all did either go full blast or not at all

I don't understand these things. All I've ever tried to use are waaayy too strong and cause water to splash everywhere. I do have an under-the-toilet-seat one and I like that very much, butI never got the hand of the handheld ones

You don't have rates like that? In Austria you can just get a rate that will charge the 15 minute spot market price. That can be even negative during the day, but then also might be quite high at other periods.

Balatro is indie, songs isn't it? Developed by a single dude with probably zero budget

I think this is a perfect strategy - you can sell code, and if any of it contains issues/bugs/gaping security holes you can just blame your customer for not checking the AI output

In Europe you still need to give way for cars that are crossing straight from the other side when you want to turn left, and take care of pedestrians that also have green on a right hand turn. Granted, not all crossings are like this, but many are.

might also be to teach actually reading the instructions instead of blindly typing pi into the calculator

I didn't think of that - also for nvim you typically pull plugins from git repositories

I used it for a bit and it is working quite well with small vaults. But the memory issue is real - by now obsidian always crashes when I try to sync via git on Android as my vault increased in size by quite a bit.

I just didn't plot anything anymore tbh. I originally wanted to make stencils for electro-etching but I realized that I don't really have that much of use for it.

I did it with my ender 3, using a printed bracket to hold the knife. It's a hassle to use and I barely use it because it's such a pita. I managed to make a few nice cutouts though so it's definitely possible. I just wouldn't recommend it.

So, a typical pupil is around 2 mm in diameter in bright conditions. With the Rayleigh limit that results in an angular resolution of 1.22 * 60010^-9 m / 210^-3 m = 3.66*10^-4 rad

At a distance of 5 x 3 mi = 15 mi = 24.1 km this corresponds to a point to point distance of

tan(a/2) = (d/2)/l

d = tan(a/2) * l * 2 = tan(3.66*10^-4) * 24100 * 2 = 8.8 m

So in conclusion, with regular, human-like eyes he could discern points that are at least 8.8 m apart in the best case scenario. Discerning hair color from the color of the clothes would need a much higher resolution, and the horsemen are probably not 10 m apart from each other either. And again, this is a theoretical limit, real-world resolution would probably be significantly lower.