Programmer Humor

If you’re getting a segfault in C++, it’s also cause you used unsafe code. It’s just not officially enclosed in an “unsafe” block.

The only way to make Rust segfault is by performing unsafe operations.

Challange accepted. The following Rust code technically segfaults:

fn stackover(a : i64) -> i64 {
    return stackover(a);
}


fn main() {
    println!("{}", stackover(100));
}

A stack overflow is technically a segmentation violation. At least on linux the program recives the SIGSEGV signal. This compiles and I am no rust dev but this does not use unsafe code, right?

While the compiler shows a warning, the error message the program prints when run is not very helpfull IMHO:

thread 'main' has overflowed its stack
fatal runtime error: stack overflow
[1]    45211 IOT instruction (core dumped)  ../target/debug/rust

Edit: Even the compiler warning can be tricked by making it do recusion in pairs:

fn stackover_a(a : i64) -> i64 {
    return stackover_b(a);
}

fn stackover_b(a : i64) -> i64 {
    return stackover_a(a);
}

fn main() {
    println!("{}", stackover_a(100));
}