this post was submitted on 16 Jul 2025
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So of course both of these are slight simplifications, but what is the connection between the two? If the earth is basically a circle, is an ellipse just a parabola stretched around a circle? Is a parabola just an approximation of a tiny part of an ellipse? How high do you have to be before you change your calculations of a trajectory?

The Math ain't mathing.

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[โ€“] [email protected] 48 points 1 day ago (1 children)

When you throw something on earth and calculate it as a parabola, that's based on the approximation that the force of gravity is constant across the trajectory. It's actually a tiny bit weaker 20 feet up than at ground level, but the difference is so small that you can ignore it. The trajectory in a constant gravational field is parabolic.

When something is high enough that you're doing orbital calculations, you have to take the inverse square law into account. The elliptical orbit is a consequence of the gravitational force being inversely proportional to the square of the distance. It doesn't apply if the force is constant.

You can also say, look at a small segment of the pointy part of a very skinny ellipse, and it will look approximately like a parabola.

[โ€“] [email protected] 4 points 1 day ago

Great explanation!